16(t^2+2t+4)=0

Solution for 16(t^2+2t+4)=0 equation:

Simplifying
16(t2 + 2t + 4) = 0

Reorder the terms:
16(4 + 2t + t2) = 0
(4 * 16 + 2t * 16 + t2 * 16) = 0
(64 + 32t + 16t2) = 0

Solving
64 + 32t + 16t2 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), '16'.
16(4 + 2t + t2) = 0

Ignore the factor 16.
Subproblem 1
Set the factor '(4 + 2t + t2)' equal to zero and attempt to solve:

Simplifying
4 + 2t + t2 = 0

Solving
4 + 2t + t2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + 2t + -4 + t2 = 0 + -4

Reorder the terms:
4 + -4 + 2t + t2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 2t + t2 = 0 + -4
2t + t2 = 0 + -4

Combine like terms: 0 + -4 = -4
2t + t2 = -4

The t term is 2t.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2t + 1 + t2 = -4 + 1

Reorder the terms:
1 + 2t + t2 = -4 + 1

Combine like terms: -4 + 1 = -3
1 + 2t + t2 = -3

Factor a perfect square on the left side:
(t + 1)(t + 1) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.